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=L_POLYINT(coeffs, [k])
ArgumentDescriptionExample
coeffsCoefficients of the original polynomial in decreasing order of power
k(default=0) The constant of integration0

Description

L_POLYINT returns the integral of polynomial p(x). The integral of a polynomial p(x) of degree n is a new polynomial q(x) of degree n+1. If you know what the constant of integration should be, you can include that constant as a scalar k. Otherwise, it is assumed to be zero.

$$p(x) = β_nx^n + β_{n-1}x^{n-1} + … + β_1x + β_0$$

$$q(x) = \int β_3x^3+β_2x^2+β_1x+β_0 dx=\frac{β_3x^4}{4}+\frac{β_2x^3}{3}+\frac{β_1x^2}{2}+β_0x+k$$

As an example, what is the integral of p(x)=2x^3+5x+6? Remember to include 0 as the coefficient of the x^2 term.

=LET(
    k, 42,
    px, {2,0,5,6},
    L_POLYINT(px,k)
)

Result: {0.5, 0, 2.5, 6, 42}
q(x) = 0.5x^4 + 0x^3 + 2.5x^2 + 6x + 42

You can specify values for a and b using L_POLYINT(px,,a,b) to evaluate \(\int_a^b p(x) dx = q(b)-q(a)\). The constant k is not needed in this case and can be left blank. See the following example:

=LET(
    px, {2,0,5,6},
    L_POLYINT(px,,-1,5)
)

Result: 408

Lambda Formula

This code for using L_POLYINT in Excel is provided under the License as part of the LAMBDA Library, but to use just this function, you may copy the following code directly into your spreadsheet.

Code for AFE Workbook Module (Excel Labs Add-in)

/**
* Returns the integral of the polynomial with integration constant k,
* optionally evaluated from a to b
*/
L_POLYINT = LAMBDA(coeffs,[k],[a],[b],
LET(doc,"https://www.vertex42.com/lambda/polyint.html",
    k,IF(ISBLANK(k),SEQUENCE(ROWS(coeffs),1,0,0),IF(ROWS(k)=1,SEQUENCE(ROWS(coeffs),1,k,0),k)),
    n,COLUMNS(coeffs),
    powers,SEQUENCE(1,n,n,-1),
    qx,HSTACK(coeffs/powers,k),
    IF(AND(NOT(ISBLANK(a)),NOT(ISBLANK(b))),
        BYROW(qx,LAMBDA(row,L_POLYVAL(row,b)-L_POLYVAL(row,a))),
        qx
    )
));

Named Function for Google Sheets

Name: L_POLYINT
Description: Returns the integral of a polynomial as another polynomial
Arguments: coeffs, k, a, b
Function:

LET(doc,"https://www.vertex42.com/lambda/polyint.html",
    k,IF(ISBLANK(k),SEQUENCE(ROWS(coeffs),1,0,0),IF(ROWS(k)=1,SEQUENCE(ROWS(coeffs),1,k,0),k)),
    n,COLUMNS(coeffs),
    powers,SEQUENCE(1,n,n,-1),
    qx,HSTACK(ARRAYFORMULA(coeffs/powers),k),
    IF(AND(NOT(ISBLANK(a)),NOT(ISBLANK(b))),
        BYROW(qx,LAMBDA(row,L_POLYVAL(row,b)-L_POLYVAL(row,a))),
        qx
    )
)

L_POLYINT Examples

Example
Find the area under \( (x^2+3x-1)(4x+1) \) between a=0 and b=10. Use L_POLYMULT to multiply the two polynomials, then find q(x) and evaluate the integral using L_POLYVAL(qx,b)-L_POLYVAL(qx,a).
Test: Copy and Paste this LET function into a cell
=LET(
    px_1, {1,3,-1},
    px_2, {4,1},
    px, L_POLYMULT(px_1,px_2),
    qx, L_POLYINT(qx),
    L_POLYVAL(qx,10)-L_POLYVAL(qx,0)
)

Result: 14273.333
Disclaimer: This article is meant for educational purposes only. See the License regarding the LAMBDA code, and the site Terms of Use for the documentation.